How to Find Dimensions of Rectangle if You Only Know the Area
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The rectangle below has a perimeter of 54. Notice the lengths of the unknown side. That is, discover S.
Explanation:
For a rectangle, its perimeter is the sum of all for sides. Nosotros can write
Simplify
Solve for South
Given a rectangle with a length units longer than its width and an surface area of square units, find the length of the rectangle's shortest side.
Right respond:
Explanation:
The given rectangle has a length that is units longer than its width. This tin be expressed in the following equation, where is the length and is the width of the rectangle.
Since the expanse of the rectangle is equal to its length multiplied past its width (), and the area of the rectangle is given, the following equation must exist true.
Replacing in this equation with its value stated in the first equation results in the following.
Distribute the variable into the parentheses.
Factor the polynomial.
and are both solutions for this equation, just is not valid equally a width for a rectangle. The width of the rectangle is units, which is the shorter side since the length is units longer.
There is a regtangular contend surrounding a park. The perimeter of the argue is . What is the width of the contend if the length is ?
Right answer:
A rectangle has a perimiter of 36 inches and a length of 12 inches. What is the width of the rectangle in inches?
Correct answer:
Caption:
To detect the width, multiply the length that you have been given by 2, and decrease the result from the perimeter. You now have the full length for the remaining ii sides. This number divided by ii is the width.
A rectangle four and a half times every bit long equally it is wide has perimeter of 272 centimeters. To the nearest tenth of a centimeter, how wide is it?
Correct answer:
Explanation:
If we call the width of this rectangle , so its length can be restated as, or, equivalently, .
The perimeter tin then be written as:
Since the perimeter of the rectangle is 272 cm, we can gear up up the following equation:
The width, in cm, of a rectangular fence is 2 more than half its length, in cm. Which of the following gives the width, w cm, in terms of length, fifty cm, of the rectangular fence?
Possible Answers:
w = 2l + two
w = ½ l – two
w = 2l – ii
w = ½ l + two
Correct respond:
w = ½ l + two
Caption:
To find the width, we must take half of the length, which means we must divide the length by ii. Then we must have 2 more than than that number, which means we must add 2 to the number. Combining these, we become:
west = ½ fifty + ii
The width of a rectangle is 2 inches longer than iii times its length. Which of the following equations gives the width, w, of the rectangle in terms of its length, fifty,?
Possible Answers:
w = 3l + 2
w = 3l – 2
w = i/3l +ii
w = 6l +ii
Correct respond:
w = 3l + 2
Explanation:
The width equals iii times the length, then 3l, plus an additional ii inches, so + 2, = 3l + 2
Your dad shows you a rectangular calibration cartoon of your house. The drawing is 6 inches by viii inches. You're trying to effigy out the bodily length of the shorter side of the house. If you know the bodily length of the longer side is 64 feet, what is the actual length of the shorter side of the house (in feet)?
Explanation:
Nosotros can solve this by setting upward a proportion and solving for 10,the length of the shorter side of the house. If the drawing is scale and is 6 : 8, then the actual house is x : 64. Then we can cantankerous multiply so that 384 = viiix. We so divide past eight to go 10 = 48.
If the perimeter of a rectangle is and the length of the rectangle is, what is the width of the rectangle?
Correct answer:
Caption:
Recollect how to find the perimeter of a rectangle.
We tin can then dispense this equation to notice the width.
Now, plug in the information given past the question to find the width.
If the perimeter of a rectangle is and the length of the rectangle is, what is the width of the rectangle?
Correct reply:
Explanation:
Think how to discover the perimeter of a rectangle.
We can then manipulate this equation to observe the width.
Now, plug in the information given by the question to find the width.
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